InterviewSolution
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InterviewSolution
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(11.The-displacement in meter of a particle moving along x-axis is given byX = 18t + 5t2Calculate(i) The instantaneous velocity att 2s(ii) Average velocity between t 2s and t- 3s(iii) Instantaneous acceleration. |
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Answer» given x = 5t2+ 18t we know that v = dx/dt = d/dt[5t2+ 18t] or v = 10t + 18 now, the instantaneous velocity at t = 2s is given as v = 10x2 + 18 or v = 38 m/s now, at t = 2s x1= 5(2)2+ 18(2) = 56m and at t = 3s x2= 5(3)2+ 18(3) =99m so, total distance travelled dx = (x2- x1) total time taken dt = 1s so, average velocity vav= dx/dt = (99 - 56) / 1 thus, vav=43 m/s dv / dt = 10a = 10 m/ s |
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