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(11) The sixth term of an A.P. is 5 times the 1st term and the eleventh term exceeds twice the fifthterm by 3. Find the 8th term.​

Answer»

he 6th term of an AP is 5 times the 1st term ⇒ The 11TH term exceeds twice the 5th term by 3 ⇒ To find: The 8TH term.Answer:Now,Using the value of 'd' that we GOT earlier,We now know the value of 'a'. Let's substitute that into the equational value of 'd' and find its actual value.Since we know the values of 'a' and 'd', let's find the 8th term.Therefore, the 8th term is 33.



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