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InterviewSolution
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12. A stone is dropped from the top of a building.a)How long does it take to fall 19.6m?b)How fast does it move at the end of this fall?c)What is its acceleration after 1 sec and 2 sec? |
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Answer» a) s=ut+(1/2)gt^2 s = 0+(1/2)gt^2 s = (1/2)gt^2 t^2= 2h/g t^2=2×19.6/9.8 t^2=2×2 t^2=4 t= 2s Ans) 2 seconds b) v^2=u^2+2gh v^2=0+2gh v^2=2gh v^2=2×9.8×19.6 v^2=19.6×19.6 v=19.6 m/s Ans) 19.6m/s c) s=1/2at^2 a= 2s/t^2 a=2×19. |
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