1.

12 seTwo bodies of different masses me and my are droppedfrom two different heights a and b. The ratio of thetime taken by the two to cover these distances are[NCERT 1972; MP PMT 1993]

Answer»

For a freely falling object :a=g;

Initial velocity=u=0 m/s

g=9.8m/s²

from second equation of motion:S=ut+1/2 at²

for First object we get :

h1= gT1²/2

⇒T1=√2h1/g

For second object we geth2=gT2²/2

⇒T2=√2h2/g

T1/T2 =√h1/h2

But here h1= a and h2 =bso, T1/T2=√a/b



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