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12 seTwo bodies of different masses me and my are droppedfrom two different heights a and b. The ratio of thetime taken by the two to cover these distances are[NCERT 1972; MP PMT 1993] |
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Answer» For a freely falling object :a=g; Initial velocity=u=0 m/s g=9.8m/s² from second equation of motion:S=ut+1/2 at² for First object we get : h1= gT1²/2 ⇒T1=√2h1/g For second object we geth2=gT2²/2 ⇒T2=√2h2/g T1/T2 =√h1/h2 But here h1= a and h2 =bso, T1/T2=√a/b |
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