1.

12, Two resistors with resistance 10 Ω and 15 Ω are to beconnected to a battery of emf 12 V so as to obtain(i) Minimum current(ii) Maximum current(a) Describe the mode of connecting the resistancesin each case.circuit in each case.

Answer»

For minimum current, Resistance has to be maximum. So they must be connected in series. Total Resistance = 10+15 = 25 ohmCurrent, I = 12/25 = 0.48 Amp

2)For maximum current, Resistance has to be minimum. So they must be connected in parallel. Total Resistance =10*15/10+15 = 6 ohmCurrent, I = 12/6 = 2.0 Amp



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