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12, Two resistors with resistance 10 Ω and 15 Ω are to beconnected to a battery of emf 12 V so as to obtain(i) Minimum current(ii) Maximum current(a) Describe the mode of connecting the resistancesin each case.circuit in each case. |
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Answer» For minimum current, Resistance has to be maximum. So they must be connected in series. Total Resistance = 10+15 = 25 ohmCurrent, I = 12/25 = 0.48 Amp 2)For maximum current, Resistance has to be minimum. So they must be connected in parallel. Total Resistance =10*15/10+15 = 6 ohmCurrent, I = 12/6 = 2.0 Amp |
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