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`_ (13)^(27) Al` is a stable isotope. `_(13)^(29) Al` is expected to disintegrated byA. `alpha` emissionB. `_(-1)^(0) beta` emissionC. Positron emissionD. Proton emission |
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Answer» Correct Answer - B Since `._(13)^(27) Al` is stable isotope , `._(13)^(29)Al` has `(n)/(P)` ratio higher than required, it will disintegrate by `beta^(-)` emission and `(n)/(P)` ratio will decrease. `._(13)^(29)Al rarr ._(14) si^(29)+._(-1)e^(0)` |
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