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`._(13)Al^(27)` is a stable isotope. `._(13)Al^(29)` is expected to disintegrate byA. `alpha-` emissionB. `beta-` emissionC. postion emissionD. proton emission |
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Answer» Correct Answer - `(b)` Nuclides having `(n)/(p) gt 1` undergoes `beta-` emission to decreases `(n)/(p)` in order to attain belt of stablitly i.e., `(n)/(p) = 1` `._(13)^(29)Al rarr ._(14)^(29)Si + ._(-1)e^(0)` |
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