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13. Find the average frictional force needed to stop a carweighing 500 kg in a distance of 25 m if the initial speedİs 72 km/h. |
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Answer» u = 5/18*72 = 20 m/secs = 25 mv = 0 (as car is made to stop)applying 3rd equation of motionv2= u2+2as0 = 400+50aa = -8 m/sec2Retardation = 8 m/sec2Retarding Force Required = Mass*Retardation = 8*500 = 4000 NHence 4000 N Of Retarding Force Is Required To Stop The Car Under The Given Circumstances |
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