InterviewSolution
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InterviewSolution
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(14 A bullet of mass 10g travelling horizontally with a velocity of 150 ms-I strikes ary wooden block and comes to rest in 0-03 s. Calculate theo the block. Also calculate the magnitude of the force exerted by the wooden block onof ldistance of penetration of the |
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Answer» mass of the bullet (m) = 10 g = (10/1000) kg =0.01 kgInitial velocity (u) = 150 m/sFinal velocity (v) = 0 m/sTime taken (t) = 0.03 seci. Calculation of the distance of penetrationof the bullet into the block:Calculation of the distance of penetrationof the bullet into the block = DisplacementDisplacement = average velocity × timeDisplacement = [(u + v) / 2] × timeDisplacement = [(150 + 0) / 2] × 0.03Displacement = 2.25 mii. Calculation ofthe magnitude of the force exerted by the wooden block on the bullet:the magnitude of the force exerted by the wooden block on the bullet = Retarding forceRetarding force = mass × reatardationRetarding force = mass ×[ (Intitial velocity - Final velocity) / t ]Retarding force = 0.01 ×[ (150 - 0) / 0.03 ] NRetarding force = [150/3] NRetarding force = 50 N |
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