14. An object 5.0 cm in length is placed at a distance of 20 cm in fro

1.	14. An object 5.0 cm in length is placed at a distance of 20 cm in front of a concavemirror of radius of curvature 30 cm. Find the position of the image, its natureand size.
Answer» ANSWER: Radius of curvature (R) = 30 cm f = R/2 = 30/2 = 15 cm u = -20 cm, h= 5 cm. 1/v +1/u = 1/f 1/v = 1/15+ 1/20 = 7/60 v = 60/7 = 8.6 cm. IMAGE is VIRTUAL and erect and formed behind the mirror. hi/h0= v/u hi/5= 8.6/20 hi = 2.2 cm. Size of image is 2.2 cm.

14. An object 5.0 cm in length is placed at a distance of 20 cm in front of a concavemirror of radius of curvature 30 cm. Find the position of the image, its natureand size.

Answer»

ANSWER:

Radius of curvature (R) = 30 cm

f = R/2 = 30/2 = 15 cm

u = -20 cm,

h= 5 cm.

1/v +1/u = 1/f

1/v = 1/15+ 1/20 = 7/60

v = 60/7 = 8.6 cm.

IMAGE is VIRTUAL and erect and formed behind the mirror.

hi/h0= v/u

hi/5= 8.6/20

hi = 2.2 cm.

Size of image is 2.2 cm.

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14. An object 5.0 cm in length is placed at a distance of 20 cm in front of a concavemirror of radius of curvature 30 cm. Find the position of the image, its natureand size.​

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14. An object 5.0 cm in length is placed at a distance of 20 cm in front of a concavemirror of radius of curvature 30 cm. Find the position of the image, its natureand size.