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|15, A ball is dropped from a height of 10 m. If the energy of the ball reduces by 40% after striking the ground,how much high can the ball bounce back? (g 10 ms |
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Answer» Given that the ball is dropped from a height, h1 = 10 mPotential energy at h1 = mgh1Given g =10 m/s2 , h1 = 10 mTherefore the potential energy at h1 = m×10×10 = 100m JOn striking the ground level, the ball looses 40% of its initial energy:i.e. (40/100)× 100m J=40m JThe energy left on striking the ground = 100 m J - 40 m J= 60 m JSo the final energy of the ball , mgh2 = 60m Ji.e h2 = (60 /10) = 6 mHence the ball will bounce back to a height of 6 m |
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