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15. A screw has a pitch equal to 0.5 mm. What should be the number of divisions on its head so as to read correct up to 0.001 mm with its help? Ans. 500​

Answer»

ANSWER:

last \: count \:  =  \:  \frac{pitch}{number \: of \: divisions}  \\

0.001 =  \frac{0.5}{n}  \\

n = 500 \\

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