15.From a point on the ground, 1 pointthe top of a tree is seen to hav

1.	15.From a point on the ground, 1 pointthe top of a tree is seen to havean angle of elevation 60°. Thedistance between the tree anda point is 50 m. Calculate theheight of the tree? *67.2 m56.8 mO66.6 m86.6 m
Answer» REFER to the ATTACHMENT for diagram In Δ ABC , $\tt \implies \tan(60) = \frac{AC}{50}$ $\tt \implies \sqrt{3} = \frac{AC}{50}$ $\tt \implies AC = \sqrt{3} \times 50$ $\tt \implies AC = 86.600 \: \: m$ The HEIGHT of tree is 86.6 m Remmember : $\tt \star \: \: Sin (\theta ) = \frac{P}{H}$ $\tt \star \: \: Cos ( \theta) = \frac{B}{H}$ $\tt \star \: \: Tan( \theta) = \frac{P}{B}$