1.

15 g ice at `0^@C` is mixed with 10 g water at `40^@C`. Find the temperature of mixture. Also, find mass of water and ice in the mixture.

Answer» Correct Answer - A::C
Heat liberated by 10g water `(at 40^@C)` when it converts into water at `0^@C`.
`Q = m_1sDeltatheta`
`=10xx1xx40`
=400cal
Mass of ice melted by this heat,
`m_2 = Q/L = 400/80 = 5g lt 15g`
Therefore, whole ice is not melted.
Temperature of mixture is `0^@C`.
Mass of water `=m_1 + m_2 = 15g`
Mass of ice = 15-`m_2` = 10g.


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