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15 g ice at `0^@C` is mixed with 10 g water at `40^@C`. Find the temperature of mixture. Also, find mass of water and ice in the mixture. |
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Answer» Correct Answer - A::C Heat liberated by 10g water `(at 40^@C)` when it converts into water at `0^@C`. `Q = m_1sDeltatheta` `=10xx1xx40` =400cal Mass of ice melted by this heat, `m_2 = Q/L = 400/80 = 5g lt 15g` Therefore, whole ice is not melted. Temperature of mixture is `0^@C`. Mass of water `=m_1 + m_2 = 15g` Mass of ice = 15-`m_2` = 10g. |
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