16 Write an expression for the amount of heat produced in a wire of re

1.	16 Write an expression for the amount of heat produced in a wire of resistance R carrying a crent i Sfortme tAn electric heater of resistance 10 รง draw,15 A from the service mams for 2 hours.Calculate0) the heat produced in the heater and energy consumed in it(ii) the power of the heater.
Answer» Consider a resistor of Resistance R. Let the current flowing through the resistor be I and potential difference across its ends be V.In time t, let Q amount of charge flows through the resistor. Work done on Moving charge will be,W =V x Q ---------(1). According to the definition of electric current,Q = I x t -----------(2). Putting equation (2) in (1),W = V x I x t.And the work done is dissipated as heat.Therefore,Heat produced, H=W=V x I x t => VIt.H= VIt.According to Ohm's law V= IR.Putting this in equation(2), we get,H= IR x It.Therefore, Heat= I^2)Rt. Hence heat produced in heater when heat=i^2rt=151510260*60=16,200,000Jouled

16 Write an expression for the amount of heat produced in a wire of resistance R carrying a crent i Sfortme tAn electric heater of resistance 10 รง draw,15 A from the service mams for 2 hours.Calculate0) the heat produced in the heater and energy consumed in it(ii) the power of the heater.

Answer»

Consider a resistor of Resistance R. Let the current flowing through the resistor be I and potential difference across its ends be V.In time t, let Q amount of charge flows through the resistor.

Work done on Moving charge will be,W =V x Q ---------(1).

According to the definition of electric current,Q = I x t -----------(2).

Putting equation (2) in (1),W = V x I x t.And the work done is dissipated as heat.Therefore,Heat produced, H=W=V x I x t => VIt.H= VIt.According to Ohm's law V= IR.Putting this in equation(2), we get,H= IR x It.Therefore, Heat= I^2)Rt.

Hence heat produced in heater when heat=i^2rt=15*15*10*2*60*60=16,200,000Jouled

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