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17. A body falls from rest in the gravitational field of the earth. The distance travelled in the fifth second of itsmotion is (g = 10m /s 2)(A) 25mイB)45m(C) 90m(D) 125m |
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Answer» a = g = 10 S(n th) = u +a/2(2n-1) S(5 th) = 0 + 10/2(2*5-1) = 5*9 = 45m |
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