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17. The friction of the air causes a vertical retardationequal to 10% of the acceleration due to gravityThe maximum height will be changed by (g 10 m/s')(1) 9%(3) 10%(2)(4)11%12%

Answer»

Time of flight T=2u sinθ/gθ

T1/T2 =g2/g1 = (g+g/10) /g

=11/10

Fractional decrease in time of flight=(T1−T2) /T1

=[ (T1/T2)−1 ] / (T1/T2)

= [ (11/10−1) ] / 11/10= 1/11

So the % decrease in flight time will be =9%



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