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17. The friction of the air causes a vertical retardationequal to 10% of the acceleration due to gravityThe maximum height will be changed by (g 10 m/s')(1) 9%(3) 10%(2)(4)11%12% |
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Answer» Time of flight T=2u sinθ/gθ T1/T2 =g2/g1 = (g+g/10) /g =11/10 Fractional decrease in time of flight=(T1−T2) /T1 =[ (T1/T2)−1 ] / (T1/T2) = [ (11/10−1) ] / 11/10= 1/11 So the % decrease in flight time will be =9% |
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