18.0 g of water completely vaporises at `100^(@)C` and 1 bar pressure and the enthalpy change in the process is40.79 kJ `mol^(-1)`. What will be the enthalpy change for vaporising two moles of water under the same conditions ? What is the standard enthalpy of vaporisation for water ?

18.0 g of water completely vaporises at `100^(@)C` and 1 bar pressure

1.	18.0 g of water completely vaporises at `100^(@)C` and 1 bar pressure and the enthalpy change in the process is40.79 kJ `mol^(-1)`. What will be the enthalpy change for vaporising two moles of water under the same conditions ? What is the standard enthalpy of vaporisation for water ?
Answer» `18.0` g of water `=` 1 mole `:. ` Standard enthalpy of vaporisation at`100^(@)C` and 1 bar pressure `=40.79 kJ mol^(-1)` Enthalpy change in vaporisationof 2 moles of water `= 2 xx 40.79 kJ = 81. 58 kJ`

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18.0 g of water completely vaporises at `100^(@)C` and 1 bar pressure and the enthalpy change in the process is40.79 kJ `mol^(-1)`. What will be the enthalpy change for vaporising two moles of water under the same conditions ? What is the standard enthalpy of vaporisation for water ?

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