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18. Two wires of the same metal have same lengthbut their cross-sections are in the ratio 3:1. Theare joined in series. The resistance of thickerwire is 10Ω. The total resistance of thecombination will be(a) 10Ω (b) 20 Ωc)40 Ω (d) 100Ω/

Answer»

Resistence of wire A =10 ohm.

therefore resistence of thinner wire=3*10=30 ohm. (R=pl/A)

total R = 10+30=40 ohm..(since they are in series)



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