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19.A boy can throw a stone up to a maximum height of10 m. The maximum horizontal distance that the boycan throw the same stone up to will beJEE mains 2012](1) 10 nm(2) 10V2 m(4) 20V2 m(3) 20 m

Answer»

Given vertical height = 10m. if we took it as max vertical height

then, u^2/2g = 10m => u^2/g = 20

As horizontal projectile range = u^2sin2∂/g

So, range is maximum when∂=45 degrees

Hence, maximum horizontal range is u^2/2g = 20,m



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