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19.At what height above the surface of earth the valueof "g" decreases by 2%? [radius of the earth is6400 km(1) 32 km(3) 128 km(2) 64 km(4) 1600 km |
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Answer» G' = g(1 -2h/R) rearrange this expression you getg'=g-2hg/Rg'-g=-2hg/Rby dividing g on both sideswe get (g'-g)/g =-2h/R -2/100= -2h/R Or h = R/100 = 6400/100 = 64 km |
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