1.

1uC and -1uC are placed at a distance of 5 cm forming a dipole. What is the amount of torque required to place the dipole perpendicularly to an electric field of 3*10^5 N/C?(a) 5*10^-3 N. m(b) 15*10^-3 N. m(c) 1*10^-3 N. m(d) 10*10^-3 N. mThis question was addressed to me during an online exam.My question is based upon Dipole in a Uniform External Field topic in portion Charges and Fields of Physics – Class 12

Answer»

The CORRECT choice is (b) 15*10^-3 N. m

Easy explanation: Dipole moment of the dipole = 1*10^-6*5*10^-2 C. m=5*10^-8 C. m. Given the electric field-intensity is E=3*10^5 N/C. Therefore required TORQUE will be P*E*sinθ where θ is the angle between the electric field and the dipole moment = 90 degrees. Therefore torque required in this case will be 5 *10^-8*3*10^5*sin 90 N. m=15*10^-3 N. m.



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