2.15 In ohm's experiment, the value of the unknown resistances were fo

1.	2.15 In ohm's experiment, the value of the unknown resistances were found to be 6.12, 6.24, 6.00,5.88,and 5.76,ohm.Calculate the absolute error, relative error and percentage error in thismeasurement.
Answer» average = (6.12 + 6.24 + 6.00 + 5.88 + 5.76)/5 = 29.30 / 5 = 5.86 ohm Absolute error \|dx1\| = 5.86 - 6.12 = 0.26 \|dx2\| = 5.86 - 6.24 = 0.38 \|dx3\| = 5.86 - 6.00 = 0.24 \|dx4\| = 5.86 - 5.88 = 0.02 \|dx5\| = 5.86 - 5.76 = 0.10 (0.26 + 0.38 + 0.24 + 0.02 + 0.10)/5 = 0.2 relative error = absolute error/actual number = 0.2 / 5.86 = 0.0341 percentage error = relative error × 100% =0.0341×100 = 3.41% *PLEASE mark as BRAINLIEST*

2.15 In ohm's experiment, the value of the unknown resistances were found to be 6.12, 6.24, 6.00,5.88,and 5.76,ohm.Calculate the absolute error, relative error and percentage error in thismeasurement.

Answer»

average

= (6.12 + 6.24 + 6.00 + 5.88 + 5.76)/5

= 29.30 / 5

= 5.86 ohm

Absolute error

|dx1| = 5.86 - 6.12 = 0.26

|dx2| = 5.86 - 6.24 = 0.38

|dx3| = 5.86 - 6.00 = 0.24

|dx4| = 5.86 - 5.88 = 0.02

|dx5| = 5.86 - 5.76 = 0.10

(0.26 + 0.38 + 0.24 + 0.02 + 0.10)/5

= 0.2

relative error = absolute error/actual number

= 0.2 / 5.86 = 0.0341

percentage error = relative error × 100%

=0.0341×100

= 3.41%

PLEASE mark as BRAINLIEST

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2.15 In ohm's experiment, the value of the unknown resistances were found to be 6.12, 6.24, 6.00,5.88,and 5.76,ohm.Calculate the absolute error, relative error and percentage error in thismeasurement.​

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2.15 In ohm's experiment, the value of the unknown resistances were found to be 6.12, 6.24, 6.00,5.88,and 5.76,ohm.Calculate the absolute error, relative error and percentage error in thismeasurement.