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2. A block slides with constant velocity on a planeinclined at an angle θ. The same block is pushedup the plane with an initial velocity vo. The distancecovered by the block before coming to rest is202g sin 04g sin θ(4) Wo sin2g |
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Answer» block moves down the plane with constant velocity it means net force is zero... force due to friction (f) = mgsin ( is the angle of plane) net retardation force when body is projected upward is (f+mgsin) f = mgsin so net retardation force = 2mgsin ma = mgsin a(retardation) = 2gsin .............1 V2= U2- 2aS finally velocity becomes 0 so U2= 2aS S = U2/2a =u2/4gsin |
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