2. A body floats in water w th 40% of itsvolume outside water, When th

1.	2. A body floats in water w th 40% of itsvolume outside water, When the samebody floats in an oil, 60% of its volumeremains outside oil. The relative densityof oil is(a) 0.9(b) .0(C) 1.2(d) 5.5
Answer» Total weight of body will be equal to weight of water surrounded by body(bouyant force),which gives us density of body. Such as If d and v are density and volume of body and w and O is density of water and oil. So Wight of body = weight of water displaced by body. dvg=w0.6vg So. d=600 kg/m3. Now in the case of oil. same concept is applied. Wight of body = Wight of oil displaced by body dvg=O0.4vg So. O = 1500 kg/m3. Now we know that. Relative density =K/2. Relative density = oil density/water density So . K/2 = 1500/1000 So K=3.

2. A body floats in water w th 40% of itsvolume outside water, When the samebody floats in an oil, 60% of its volumeremains outside oil. The relative densityof oil is(a) 0.9(b) .0(C) 1.2(d) 5.5

Answer»

Total weight of body will be equal to weight of water surrounded by body(bouyant force),which gives us density of body. Such as

If d and v are density and volume of body and w and O is density of water and oil.

So Wight of body = weight of water displaced by body.

d*v*g=w*0.6*v*g

So. d=600 kg/m3.

Now in the case of oil. same concept is applied.

Wight of body = Wight of oil displaced by body

d*v*g=O*0.4*v*g

So. O = 1500 kg/m3.

Now we know that. Relative density =K/2.

Relative density = oil density/water density

So . K/2 = 1500/1000

So K=3.

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