2. A body starts from rest with an acceleration of 2 m/s2. Calculate :

1.	2. A body starts from rest with an acceleration of 2 m/s2. Calculate :(1) velocity after 5 seconds,(ii) the distance covered in 5 seconds,
Answer» (1) using relation v = u + at v = final velocity u = initial velocity a = acceleration t = time taken v = 0 + 25 = 10 Therefore, velocity after 5 seconds is 10 m/s (2) using relation s = ut + 1/2at^2 s = 05 + 1/22(5)^2 s = 0 + 25 = 25 Therefore, distance covered is 25 m

2. A body starts from rest with an acceleration of 2 m/s2. Calculate :(1) velocity after 5 seconds,(ii) the distance covered in 5 seconds,

Answer»

(1) using relation v = u + at v = final velocity u = initial velocity a = acceleration t = time taken

v = 0 + 2*5 = 10 Therefore, velocity after 5 seconds is 10 m/s

(2) using relation s = ut + 1/2at^2 s = 0*5 + 1/2*2*(5)^2 s = 0 + 25 = 25 Therefore, distance covered is 25 m

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2. A body starts from rest with an acceleration of 2 m/s2. Calculate :(1) velocity after 5 seconds,(ii) the distance covered in 5 seconds,

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