2. A current of 3.5 ± 0.5 A flows through metallic conductor with a p

1.	2. A current of 3.5 ± 0.5 A flows through metallic conductor with a potential difference of 21 ± 1 V is applied. Find the resistance of the wire.
Answer» Answer: Explanation: => It's given that, Current through the WIRE, I = 3.5 ± 0.5 A Potential difference, V = 21 ± 1 V RESISTANCE , R = ? => As per the Ohm's law: V = IR ∴ R = V / I Resistance WITHOUT error, R = V/I = 21/3.5 = 6ᘯ. => We can do the calculation of error in resistance as below: ∆R/R = ∆V/V + ∆I/I ∴ ∆R/6 = 1/21 + 0.5/3.5 ∆R/6 = (1/21 + 1/7) ∆R = 6 × 4/21 ∆R = 24/21 ∆R = 8/7 ∆R ≈ 1.143 ∴ R = (6 ± 1.143) Ω. Thus, the resistance of the wire is (6 ± 1.143) Ω

2. A current of 3.5 ± 0.5 A flows through metallic conductor with a potential difference of 21 ± 1 V is applied. Find the resistance of the wire.

Answer»

Answer:

Explanation:

=> It's given that,

Current through the WIRE, I = 3.5 ± 0.5 A

Potential difference, V = 21 ± 1 V

RESISTANCE , R = ?

=> As per the Ohm's law:

V = IR

∴ R = V / I

Resistance WITHOUT error, R = V/I = 21/3.5 = 6ᘯ.

=> We can do the calculation of error in resistance as below:

∆R/R = ∆V/V + ∆I/I

∴ ∆R/6 = 1/21 + 0.5/3.5

∆R/6 = (1/21 + 1/7)

∆R = 6 × 4/21

∆R = 24/21

∆R = 8/7

∆R ≈ 1.143

∴ R = (6 ± 1.143) Ω.

Thus, the resistance of the wire is (6 ± 1.143) Ω

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2. A current of 3.5 ± 0.5 A flows through metallic conductor with a potential difference of 21 ± 1 V is applied. Find the resistance of the wire.

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