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2. A farmer moves along the boundary of a square field of side 10 min 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position? |
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Answer» Answer: Here's your answer Explanation: Total distance traveled by farmer in 40s=4×10=40m Total time taken =2min×20sec=140sec Total number of rounds = 40 140 =3.5 If farmer starts from A, then after 3.5 rounds, he reaches to point ′ C ′ . Therefore, displacement =AC. Now, ABCD is a square, then △ABC is a right angled △. Using PYTHAGORAS theorem, AC =AB 2 +BC 2 ⇒AC= 10 2 +10 2
= 200 =10 2
AC=10×1.414=14.14m Hence, displacement =14.14m Hope it helps you Pls mark me the brainliest |
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