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2. () An electric refrigeralor rate 400 W operates S hours per day. What is the cost ofopezate it for 30 days at 5.00 per unit? |
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Answer» Here,Power P=400 W=400/1000 kW=0.40 kW Time t=8 x 30=240 hours Now electrical energy is given by, E=P x t =0.40 x 240=96 kWh Thus the electric energy consumed by the refrigerator in a month of 30 days is 96 kWh. Cost of 96 kWh of electricity=96 x 5= Rs. 480 |
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