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2. If five resistances, each of value 0.2 ohm, are connected in series, what will be the resultan3. State the law of combination of resistances in parallel |
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Answer» if 5 resistance of 0.2 ohm are connected in series then R=R1+R2+R3+R4+R5. THEREFORE 0.2+0.2+0.2+0.2+0.2=1.0ohm answer |
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