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                                    2. Joseph jogs from one end A to the other end B of a straight300 m road in 2 minutes 30 seconds and then turns arounand jogs 100 m back to point C in another 1 minute. What arJoseph's average speeds and velocities in jogging (a) from AtB and (b) from A to C? | 
                            
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Answer»  Question you have submitted is incomplete. Please post a complete question. Velocity = dispacement / timeSpeed = distance / time a) when he jogs from A to B on a straight road,displacement = distance = 300mtime = 2 minutes 30 seconds = 150 s velocity = 300/150 = 2 m/sspeed = 300/150 = 2m/s b)when he jogs from A to B and turns back to C,displacement = 300-100 = 200mdistance = 300+100 = 400mtime = 3 minute 30 second = 210 s velocity = 200/210 = 20/21 m/sspeed = 400/210 = 40/21 m/s  | 
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