1.

2 Men And 7 Boys Can Do A Piece Of Work In 14 Days; 3 Men And 8 Boys Can Do The Same In 11 Days. Then, 8 Men And 6 Boys Can Do Three Times The Amount Of This Work In?

Answer»

(2 x 14) men +(7 x 14) boys = (3 x 11) men + (8 x 11) boys

=>5 men= 10 boys => 1man= 2 boys

Therefore, (2 men+ 7 boys) = (2 x 2 +7) boys = 11 boys

( 8 men + 6 boys) = (8 x 2 +6) boys = 22 boys.

Let the required number of DAYS be x.

More boys , Less days (INDIRECT proportion)

More work , More days (Direct proportion)

Boys22:11Work1 : 3}?? 14:x

Therefore, (22 * 1 * x) = (11 * 3 * 14)

=> x = 21 

Hence, the required number of days = 21.

(2 x 14) men +(7 x 14) boys = (3 x 11) men + (8 x 11) boys

=>5 men= 10 boys => 1man= 2 boys

Therefore, (2 men+ 7 boys) = (2 x 2 +7) boys = 11 boys

( 8 men + 6 boys) = (8 x 2 +6) boys = 22 boys.

Let the required number of days be x.

More boys , Less days (Indirect proportion)

More work , More days (Direct proportion)

Boys22:11Work1 : 3}?? 14:x

Therefore, (22 * 1 * x) = (11 * 3 * 14)

=> x = 21 

Hence, the required number of days = 21.



Discussion

No Comment Found