| 1. |
2 Men And 7 Boys Can Do A Piece Of Work In 14 Days; 3 Men And 8 Boys Can Do The Same In 11 Days. Then, 8 Men And 6 Boys Can Do Three Times The Amount Of This Work In? |
|
Answer» (2 x 14) men +(7 x 14) boys = (3 x 11) men + (8 x 11) boys =>5 men= 10 boys => 1man= 2 boys Therefore, (2 men+ 7 boys) = (2 x 2 +7) boys = 11 boys ( 8 men + 6 boys) = (8 x 2 +6) boys = 22 boys. Let the required number of DAYS be x. More boys , Less days (INDIRECT proportion) More work , More days (Direct proportion) Boys22:11Work1 : 3}?? 14:x Therefore, (22 * 1 * x) = (11 * 3 * 14) => x = 21 Hence, the required number of days = 21. (2 x 14) men +(7 x 14) boys = (3 x 11) men + (8 x 11) boys =>5 men= 10 boys => 1man= 2 boys Therefore, (2 men+ 7 boys) = (2 x 2 +7) boys = 11 boys ( 8 men + 6 boys) = (8 x 2 +6) boys = 22 boys. Let the required number of days be x. More boys , Less days (Indirect proportion) More work , More days (Direct proportion) Boys22:11Work1 : 3}?? 14:x Therefore, (22 * 1 * x) = (11 * 3 * 14) => x = 21 Hence, the required number of days = 21. |
|