A Sum Of Money Amounts To Rs.6690 After 3 Years And To Rs.10,035 Afte

1.	A Sum Of Money Amounts To Rs.6690 After 3 Years And To Rs.10,035 After 6 Years On Compound Interest.find The Sum?
Answer» Let the sum be Rs.P.then P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(II) On DIVIDING,we GET (1+R/100)^3=10025/6690=3/2. SUBSTITUTING this value in (i),we get: P(3/2)=6690 or P=(66902/3)=4460 Hence,the sum is rs.4460. Let the sum be Rs.P.then P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(ii) On dividing,we get (1+R/100)^3=10025/6690=3/2. Substituting this value in (i),we get: P(3/2)=6690 or P=(66902/3)=4460 Hence,the sum is rs.4460.

A Sum Of Money Amounts To Rs.6690 After 3 Years And To Rs.10,035 After 6 Years On Compound Interest.find The Sum?

Answer»

Let the sum be Rs.P.then

P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(II)

On DIVIDING,we GET (1+R/100)^3=10025/6690=3/2.

SUBSTITUTING this value in (i),we get:

P*(3/2)=6690 or P=(6690*2/3)=4460

Hence,the sum is rs.4460.

Let the sum be Rs.P.then

P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(ii)

On dividing,we get (1+R/100)^3=10025/6690=3/2.

Substituting this value in (i),we get:

P*(3/2)=6690 or P=(6690*2/3)=4460

Hence,the sum is rs.4460.