InterviewSolution
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InterviewSolution
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2 mole of ideal momoatmic gas was subjected to reversible adiabatic compression from initianl state of P= 1 and T = 300 K till the pressrue is `4sqrt(2)` atm and temperature is TK . The gas is then subjected to reversible isothermal expansion at T K till the internal pressure is one atm . The gas is now isobarically cooled to attain initial state. Find `W_(Net)` ( in calorie) for whole process . [Use In 2=0.7] |
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Answer» Correct Answer - `-1.2 xx 10^(03) or - 1.19 xx 10 ^(03)("taking R= 1.98")` `T_(2)= T_(1)(P_(1)/(P_(2)))^(((1-gamma)/(gamma))` ` = 600 K` `W_(I)= W_("rev")= nC_(V)[T_(2)- T_(1)] = 2 xx (3)/(2) R xx 300` `= 900 R` `W_(II)= - 2.303 nRT log .(P_(1))/(P_(2)) = - 2xx R xx 600 In ((4sqrt(2))/(1))` `W_(III) = - PDeltaV = - nRT = - 1200R xx (5)/(2) xx 0.7 = - 2100 R` `W_("Total") = 900 R - 2100 R + 600 R` ` = - 600 R = - 1200 cal` |
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