InterviewSolution
Saved Bookmarks
| 1. |
20. A ball is thrown vertically upwards from the topof a tower with an initial velocity of 19.6 m s-1The ball reaches the ground after 5 s. Calculate:(i) the height of the tower, (ii) the velocity of ballon reaching the ground. Take g = 9.8 m s-2.Ans, (i) 24-5 m (ii) 29.4 m s-1. |
|
Answer» V=0u=19.6total time=5secg=9.8m/s squaret= u/g= 19.6/9.8=2sec to go uptherefore time to come down =3secheight = u square/2g=(19.6) square/2*9.8=19.6mheight =1/2gt square1/2 (9.8)*(3)square=44.1mheight of the building =44.1-19.6=24.5mv=gt= 9.8*3=29.4m hit like if you find it useful |
|