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20. A particle is thrown vertically up with a velocity of 50 m/s, what will be its velocity at highestpoint of journey? How high would the particle rise? What time it takes to reach the highest poin(Take the value of g-10 m/s)

Answer»

U= 50m/sg= -10m/s^2

The velocity at the highest point will be 0 m/sThus v=0

Height can be calculated by

2gs=v^2-u^2-20s= -2500s= 125m

Time :v= u+gt0=50-10t-50=-10tt= 5sec

I am not able to understand??



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