InterviewSolution
 Saved Bookmarks
    				| 1. | 
                                    20 A particle is thrown vertically up with a velocity of 50 m/s. what will be its velocity at highestpoint of journey? How high would the particle rise? What time it takes to reach the highest point?(Take the value of g= 10 m/ sy(1+2+2)2.25 | 
                            
| 
                                   
Answer»  U= 50m/sg= -10m/s^2 The velocity at the highest point will be 0 m/sThus v=0 Height can be calculated by 2gs=v^2-u^2-20s= -2500s= 125m Time :v= u+gt0=50-10t-50=-10tt= 5sec  | 
                            |