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20 A particle is thrown vertically up with a velocity of 50 m/s. what will be its velocity at highestpoint of journey? How high would the particle rise? What time it takes to reach the highest point?(Take the value of g= 10 m/ sy(1+2+2)2.25

Answer»

U= 50m/sg= -10m/s^2

The velocity at the highest point will be 0 m/sThus v=0

Height can be calculated by

2gs=v^2-u^2-20s= -2500s= 125m

Time :v= u+gt0=50-10t-50=-10tt= 5sec



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