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21:A car moving with a speed of 50 km/h canbe stopped by brakes after at least 6 m.What will be the minimum stoppingdistance, if the same car is moving at aspeed of 100km/h'?[Ans. 24 m)

Answer»

Initial velocity, u = 50 km/h = 50 × (5/18) = 250/18 m/s

Final velocity, v = 0

Distance travelled before coming to rest, s = 6 m

Using, v2= u2+ 2as

=> a = -u2/(2s)

=> a = -16.075 m/s2

Again,

u = 100 km/h = 500/18 m/s

v = 0

a = -16.075 m/s2

Now, v2= u2+ 2as

=> s = -u2/(2a) = 24 m



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