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2114. Calculate the force experienced by anegative charge of 1.5 x 10 °C placed in anelectric field of 5.4 x 106 NC-1. (-8.1 x10-3N) |
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Answer» A negative charge of amount 1.5 × 10^−9 C is placed in the electric field E of 5.4 × 10^6 NC^-1 q = - 1.5 × 10^−9 C Force experienced by the negative charge = F ∴F = qE = - 1.5 × 10^−9 × 5.4 × 10^6 = - 8.1 × 10^−3 N Let number of days required to complete work when 3 more man joined = x Then,20*18 = 20*3 + 23*x 20*(18 - 3) = 23*x 20*15 = 23*x x = 300/23 = 13 Therefore, 13 more days require to finish work |
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