1.

216 drops of same radius are charged to 10volt each. These drops coalesce to form a bigger drop.calculate the potential of bigger drop.​

Answer»

DEAR student,

● Answer -

V' = 360 V

◆ Explanation -

Let r & R be RADII of small & large drops respectively.

n(4/3)πr³ = (4/3)πR³

R³ = nr³

R³ = 216 × r³

R = ∛216 × r

R = 6r

Potential difference of the drop is related to the radius as -

V ∝ r²

That is,

V'/V = (R/r)²

V'/10 = (6r/r)²

V' = 10 × 6²

V' = 360 V

Therefore, potential of the BIGGER drop is 360 V.

Thanks Buddy.


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