1.

22. In the arrangement as shown, tension T2 is(g = 10 m/s2)60°T.30%T.210 kg

Answer»

Given :m=10kgg=10m/s2

When a body of mass m is suspended by two strings making an angleα and β with horizontal then:T1=mgcosβ/sin(α+β)T2=mgcosα/sin(α+β)

β=30α=60T2=10x10xcos(60)/sin(60+30)=100x(1/2) / 1=50N∴Tension T2=50N

no it's wrong

t2 is 50 newton he is right

no ans is 100 N

can u plz tell the direction of tensions



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