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22. In the arrangement as shown, tension T2 is(g = 10 m/s2)60°T.30%T.210 kg |
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Answer» Given :m=10kgg=10m/s2 When a body of mass m is suspended by two strings making an angleα and β with horizontal then:T1=mgcosβ/sin(α+β)T2=mgcosα/sin(α+β) β=30α=60T2=10x10xcos(60)/sin(60+30)=100x(1/2) / 1=50N∴Tension T2=50N no it's wrong t2 is 50 newton he is right no ans is 100 N can u plz tell the direction of tensions |
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