22. What will be the output of thefollowing programint a, b=4;for(a=6;

1.	22. What will be the output of thefollowing programint a, b=4;for(a=6; a
Answer» Required Answer:- Correct Co‎de: int a, b=4; for(a=6;a<=24;a+=6) { if(a%b==0) break; } System.out.println(a); Output: 12 Explanation: The given loop iterates in the range 6 to 24. Here, initial value of a is 6. After each iteration, its value is INCREMENTED by 6. So, when a is 6, a%b==0 is FALSE and so, the break statement will not be executed. After the FIRST iteration, a becomes 12 i.e., its value is incremented by 6. So, a%b==0 becomes true as 12 is divisible by 4. So, the break statement is executed. Loop is terminated at this point. Final value of a becomes 12 which is displayed on the screen. See the ATTACHMENT for output. •••♪

22. What will be the output of thefollowing programint a, b=4;for(a=6; a

Answer»

int a, b=4;

for(a=6;a<=24;a+=6) {

if(a%b==0)

break;

}

System.out.println(a);

The given loop iterates in the range 6 to 24.
Here, initial value of a is 6. After each iteration, its value is INCREMENTED by 6.
So, when a is 6, a%b==0 is FALSE and so, the break statement will not be executed.
After the FIRST iteration, a becomes 12 i.e., its value is incremented by 6. So, a%b==0 becomes true as 12 is divisible by 4. So, the break statement is executed. Loop is terminated at this point.
Final value of a becomes 12 which is displayed on the screen.

See the ATTACHMENT for output.

•••♪