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26. A mass of M kg is suspended by aweightless string. The horizontal force thatis required to displace it until the stringmakes an angle of 45° with the initialvertical direction is:(A) Mg(C) Mg (V2-1) (D) Mgx (V2+1)(B) Mg/ /2 |
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Answer» The work done by the force will be equal to the potentail energy gained by the mass. Let L be the length of the string , F.d= MgL (1 -cos45 ) The horizontal displacement of the mass is d= L sin 45 F L sin45 = Mg L(1 - 45) F = Mg (sq. root 2 - 1) |
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