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26. In a factory it is desired to lift 2000 kg of metal througha distance of 12 m in 1 minute. Find the minimumhorsepower of the engine to be usedanel to

Answer»

m=2000 kg

s=12 m

t=60 sec

p= w/t

p= ma/t (w=ma)

p=mgh/t (a=gh)

p=2000*9.8*12/60

p=3920 watt.

horse power = 3920/746

= 5.3 hp



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