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26. In a factory it is desired to lift 2000 kg of metal througha distance of 12 m in 1 minute. Find the minimumhorsepower of the engine to be usedanel to |
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Answer» m=2000 kg s=12 m t=60 sec p= w/t p= ma/t (w=ma) p=mgh/t (a=gh) p=2000*9.8*12/60 p=3920 watt. horse power = 3920/746 = 5.3 hp |
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