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27. The maximum height attained by a ball projected with speed 20 ms-1 at an angle 45 with the horizontal is[take g 10 ms-2.](1) 40 m(3) 10 m(2) 20 m(4) 30 m

Answer»

Given,

u = 20m/s

θ = 45°

Maximum height in projectile is given by,

h = u²sin²θ/2g

= (20)²sin²45°/2*9.8

= 100/9.8

= 10.204 m

Thus, maximum height attained by the ball is 10.204 m.



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