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27. The maximum height attained by a ball projected with speed 20 ms-1 at an angle 45 with the horizontal is[take g 10 ms-2.](1) 40 m(3) 10 m(2) 20 m(4) 30 m |
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Answer» Given, u = 20m/s θ = 45° Maximum height in projectile is given by, h = u²sin²θ/2g = (20)²sin²45°/2*9.8 = 100/9.8 = 10.204 m Thus, maximum height attained by the ball is 10.204 m. |
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