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.28 A stone of mass 4kg is whirled in a horizontalcircle of radius 1m and makes 2 rev/sec. Themoment of inertia of the stone about the axisof rotation is(A) 64 kg x m2(C) 16 kg x m(B) 4 kg × m(D) 1 kg x m |
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Answer» By using the Basic formula i.e I = MR^2Where M = 4Kg , R = 1mI = 4 x 1 ^2 = 4Kgm^2 thanku |
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