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29.2% (W/W) HCI stock solution has a density of 1.25 g `mL^(-1)`. The molecular mass of HCI is 36.5 g `mol^(-1)` Calculate the volume (mL) of stock solution required to prepare 200 mL of 0.4 M HCI |
Answer» Mass of HCI=29.2g, Mass of solution = 100g `"Volume of solution"=((100g))/((1.25" g mL"^(-1)))=80mL=0.08 L` `M=("Mass of HCI/Molar mass")/("Volume of solution in litres")` `=((29.2g)//(36.5" g mol"^(-1)))/((0.08 L))=10M` `M_(1)V_(1)=M_(2)V_(2),(10M)xxV_(1)=(0.4M)xx(200 mL)` `V_(1)=((200mL)(0.4))/((10M))=8mL.` |
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