1.

29.2% (W/W) HCI stock solution has a density of 1.25 g `mL^(-1)`. The molecular mass of HCI is 36.5 g `mol^(-1)` Calculate the volume (mL) of stock solution required to prepare 200 mL of 0.4 M HCI

Answer» Mass of HCI=29.2g, Mass of solution = 100g
`"Volume of solution"=((100g))/((1.25" g mL"^(-1)))=80mL=0.08 L`
`M=("Mass of HCI/Molar mass")/("Volume of solution in litres")`
`=((29.2g)//(36.5" g mol"^(-1)))/((0.08 L))=10M`
`M_(1)V_(1)=M_(2)V_(2),(10M)xxV_(1)=(0.4M)xx(200 mL)`
`V_(1)=((200mL)(0.4))/((10M))=8mL.`


Discussion

No Comment Found

Related InterviewSolutions