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A complex is represented as `CoCl_(3) . XNH_(3)`. Its `0.1` molal solution in aqueous solution shows `Delta T_(f) = 0.558^(circ). (K_(f)` for `H_(2)O` is `1.86 K "molality"^(-1))` Assuming `100%` ionisation of complex and co-ordination number of `Co` as six, calculate formula of complex. |
Answer» Correct Answer - `[Co(NH_(3))_(5)Cl]Cl_(2)` `Delta"T"_("f")=[1+("n"-1)alpha]"K"_("f")xx"Molality"` `0.558=[1+("n"-1)xx1]xx1.86xx0.1` `"n"=(0.558)/(1.86xx0.1)` `"n"=3` `therefore "formula of complex"=["CO"("NH"_(3))_(5)"Cl"]"Cl"_(2)` |
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