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A compound `MX_(2)` with molar mass of 80 g is dissolved in a solvent having density 0.4 g `mL^(-1)`. Assuming that there is no change in volume upon dissociation, what is the molality of a 3.2 molar solution ? |
Answer» 3.2 mola solution contains solute=3.2 mol Consider that the volume of solution =1L Since there is no change in volueme, on dissolution of the solvent, volume solvent = 1L Mass of the solvent = `vxxd` =`(100mL)xx(0.4 mg L^(-1))=400 g=0.4 kg` `("Molality of solution")=("No. of moles of solute")/("Mass of solvent in kg")` `=((3.2mol))/((0.4 kg))=8 "kg mol"^(-1)=8` molal |
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