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29: A student starts from his house with a speed2kmph and reaches his college 3 min late.Next day he increases his speed by lkmphand reaches college 3 min earlier the distancebetween his house and college is |
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Answer» Answer: 0.6km Explanation: given u=2×5/18=5/9 h=60min 1min=1/60 3min=1/20 the TRAVEL distance from his HOME to his college is same if he travel SLOWER and FASTER the distance willnot change so 2(t+1/20)=3(t-1/20) 2t-3t=-3/20-1/10 -1t=-3-2/20=1/4 d=2(1/4+1/20)=5+1/10 6/10 0.6km is ANS |
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